An exponential grows in proportion to its own size; the constant of proportionality is \(\ln a\).
\[\frac{d}{dx}a^{x} = a^{x}\ln a\]
What it says
Exponential functions are the ones whose rate of change is proportional to their current value — populations, compound interest, radioactive decay. Differentiating \(a^{x}\) returns \(a^{x}\) again, multiplied by a fixed number.
That number is \(\ln a\). It comes out of the limit \(\lim_{h \to 0}\frac{a^{h} - 1}{h} = \ln a\), and it is what makes base \(e\) special: \(\ln e = 1\), so \(\frac{d}{dx}e^{x} = e^{x}\) exactly. \(e\) is precisely the base for which the constant is one.
Any other base can be routed through \(e\) if you prefer: \(a^{x} = e^{x\ln a}\), and the chain rule then hands back \(e^{x\ln a}\ln a = a^{x}\ln a\).
When it applies
The base is constant and the variable sits in the exponent.
\(e^{x}\) and \(\exp(x)\), the special case where the extra factor is \(1\).
With the chain rule when the exponent is a function: \(\left(a^{u}\right)' = a^{u}\ln a \cdot u'\).
Five worked examples
Every line is the step the calculator would show, in the order it applies them. Each graph
is live: hover it to read both curves and see the tangent whose slope is the derivative,
drag to pan, scroll to zoom.
1
Example 1
\[\frac{d}{dx}\left[e^{x}\right]\]
Here \(a = e\), and \(\ln e = 1\).
\[\frac{d}{dx}\left[e^{x}\right] = e^{x}\ln e\]
The extra factor is \(1\).
\[= e^{x}\]
Answer
\[e^{x}\]
The two curves lie exactly on top of each other. This is what "its own derivative" looks like: at every height, the steepness equals the height. Hover anywhere and the f and f′ readouts agree to the last digit.
The only function (up to a constant multiple) that is its own derivative.
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